Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?

JaKXz asked Feb 10, 2022

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JaKXz asked Feb 10, 2022

by JaKXz

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25 votes

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Answer:

y = -2x +1

Explanation:

The derivative of the function is ...

f'(x) = 3x^2 -2

so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...

y = -2x +1

Alvaro Castro answered Feb 17, 2022

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