299,752 views
19 votes
19 votes
Can someone help me asap please​

Can someone help me asap please​-example-1
User Steven Pessall
by
2.8k points

1 Answer

18 votes
18 votes

Answer:

Resultant force is 20 N

Step-by-step explanation:

Resolving vertically:


{ \sf{F_(y) = (8 \cos 30 \degree) + (12 \cos 30 \degree) }} \\ { \sf{ \sum F_(y) = 17.3 \: newtons }}

Resolving horizontally:


{ \sf{F_(x) = (8 \sin 30 \degree) + (12 \sin 30 \degree) }} \\ { \sf{ \sum F _(x) = 10 \: newtons}}

Resultant force:


{ \boxed{ \bf{F = \sqrt{ {F _(x) }^(2) + {F _(y) }^(2) } }}} \\ { \sf{F = \sqrt{ {17.3}^(2) + {10}^(2) } }} \\ { \sf{F = √(399.29) }} \\ F = 19.98 \approx20 \: newtons

User ErnestoC
by
2.9k points