Answer:
Solution given:
In ∆ PQR and ∆ STQ
PQ=ST=9ft given
<Q=<T given
QR=TU = 14ft [given]
S.A.S axiom therom is used to prove
∆PQR ≅ ∆STU
Since ∆PQR ≅ ∆STU
their corresponding side is equal.so
6y+5=8y
5=8y-6y
2y=5
y=5/2
now
perimeter of ∆ PQR=sum of all sides
=9ft +14ft+ 6*5/2+5=43ft