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21 votes
HCF of algebraic expression x square minus y square and x y minus y square. ​

User Juan G Carmona
by
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1 Answer

17 votes
17 votes

Answer:

(x-y+z)(x-y-z)

Given (x²-2xy+y²) - z²

= (x-y)² - z²

/* By algebraic identity

a²-2ab+b² = (a-b)² */

=[(x-y)+z][(x-y)-z]

/* a²-b² = (a+b)(a-b) */

= (x-y+z)(x-y-z)

Therefore,

(x²-2xy+y²)-z² =(x-y+z)(x-y-z)

Explanation:

x

2

y

2

=x×x×y×y

xy

2

=x×y×y

h.c.f=xy

2

User Jorawar Singh
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3.4k points