Answer:
Solution:
A.
p_x=3, G_x=\frac {100}{3}=33\frac{1}{3}p
x
=3,G
x
=
3
100
=33
3
1
p_y=5, G_y=\frac{100}{5}=20p
y
=5,G
y
=
5
100
=20
B.
100-0.25\times 100=75100−0.25×100=75
p_x=3, G_x=\frac {75}{3}=25p
x
=3,G
x
=
3
75
=25
p_y=5, G_y=\frac{75}{5}=15p
y
=5,G
y
=
5
75
=15
C.
p_x=6, G_x=\frac {100}{6}=16\frac{2}{3}p
x
=6,G
x
=
6
100
=16
3
2
D.
p_y=5, G_y=\frac{100}{4}=25p
y
=5,G
y
=
4
100
=25
2.
MU_x=68-60=8, p_x=2MU
x
=68−60=8,p
x
=2
MU_y=29-25=4, p_y-?MU
y
=29−25=4,p
y
−?
\frac {MU_x}{p_x}=\frac{MU_y}{p_y}
p
x
MU
x
=
p
y
MU
y
\frac{8}{2}=\frac {4}{p_y}
2
8
=
p
y
4
p_y=1p
y
=1