Question

Y=-1|x-2|+1 how to solve

Answer 1

if x ≥ 2, then y = x - 1

if x < 2, then y = -x + 3

Explanation:

y = 1* |x - 2| + 1

y = |x-2| + 1

*** The rule on absolute value: |a| =a, if a ≥ 0; |a| = -a, if a < 0

If x-2 ≥ 0, then |x-2| = x-2, so y = (x - 2) + 1 = x - 1; y = x - 1

So if x ≥ 2, then y = x - 1

If x-2 < 0, then |x-2| = -(x-2) = -x + 2, so y = {-x + 2} + 1 = -x + 3; y = -x + 3

So if x < 2, then y = -x + 3