210k views
17 votes
Mhanifa or someone else can you PLZ answer this

Mhanifa or someone else can you PLZ answer this-example-1

2 Answers

8 votes

Answer:


\frac{7 {n}^(2) - 41n + 8 }{ {n}^(2) - 1 }

Explanation:


(7n)/(n + 1) + (8)/(n - 7) \\ \\ = (7n(n - 7) + 8(n + 1))/((n + 1)(n - 1)) \\ \\ = \frac{7 {n}^(2) - 49n + 8n + 8 }{ {n}^(2) - 1 } \\ \\ = \frac{7 {n}^(2) - 41n + 8 }{ {n}^(2) - 1 }

User KdBoer
by
4.5k points
13 votes

Answer:

Simplified:


  • (7n)/(n + 1) + (8)/(n - 7) =

  • (7n(n - 7) + 8(n + 1))/((n + 1)(n - 7)) =

  • (7n^2 - 49n + 8n + 8)/(n^2 + n - 7n - 7) =

  • (7n^2 - 41n + 8)/(n^2 - 6n - 7)

This can be further simplified if required


  • (7n^2 - 42n -49 + n + 57)/(n^2 - 6n - 7) =

  • 7 + (n + 57)/(n^2 - 6n - 7)

User Svend
by
5.2k points