Given.
force = 16.88 N is
radius = 0.340m
an angular acceleration = 1.20rad/s^2
the formula for torque is
F*r = I*a
where I is moment of inertia
16.88*.34 = I*1.2
I = 4.78Kg-m^2
so rotational inertia I = 4.78Kg-m^2
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