Question

Answer + explanation would be appreciated

Answer 1

-2 + 2i

Explanation:

`(1 + i)^(3)`

i =
`√(-1)`

`(1 + √(-1))^3`

`[(1 + √(-1))(1 + √(-1))] (1 + √(-1))`

distribute the first 2 expressions

(1 + 2
`√(-1)` - 1 )
`(1 + √(-1))`

distribute

1 + 2
`√(-1)` - 1 +

combine like terms

-2 + 2
`√(-1)`

which is -2 + 2i