Answer:
(x-2)^2 + (y-1)^ = 1
Explanation:
First, we take the circle graphing formula, which is (x-h)^2 + (y-v)^2 = r^2 and plug in the values on the graph with the center of the circle being (h,v) and the radius being r. h = 2, v = 1, and r = 1, so we get (x-2)^2 + (y-1)^2 = 1!
I hope this helped! :D