Question

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`\sin(36) - \cos(54) \\ \tan(80) - \cot(10)`
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Answer 1

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Answer 2

Explanation:

Sin (90 - ∅) = Cos ∅

90 -54 = 36

Sin 36 = Sin (90 - 54)

= Cos 54 --------->(I)

Now, Sin (36) - Cos (54) = Cos 54 - Cos 54 {From 1}

= 0

2) tan (90-∅) = Cot ∅

Tan 80 = Tan (90 - 10)

= Cot 10 ----------(II)

Tan 80 - Cot 10 = Cot 10 - cot 10 -----------(from (II)}

= 0