Question

Find the extrema of the function y=cos2x

Answer 1

Explanation:

Find derivative of the function:

y' = -2·sin(2·x)

-2·sin(2·x) = 0

x1 = 0

x2 = 3.142

f(0) = 1

f(3.142) = 1

Answer

fmin = 1, fmax = 1