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Is a 4(2x-3)<8(x+1) always ,sometime,or never true?
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4 votes
Is a 4(2x-3)<8(x+1) always ,sometime,or never true?

User Mahdi Yamani
by
4.4k points

1 Answer

7 votes

Answer:

Explanation:

Step 1: Simplify both sides of the inequality.

8

x

−

12

<

8

x

+

8

Step 2: Subtract 8x from both sides.

8

x

−

12

−

8

x

<

8

x

+

8

−

8

x

−

12

<

8

Step 3: Add 12 to both sides.

−

12

+

12

<

8

+

12

0

<

20

User Karina H
by
4.3k points
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