Question

The armature of an AC generator has 200 turns, which are rectangular loops measuring 5 cm by 10 cm. The generator has a sinusoidal voltage output with an amplitude of 18 V. If the magnetic field of the generator is 300 mT, with what frequency does the armature turn

Answer 1

`f=9.55Hz`

Step-by-step explanation:

From the question we are told that:

Number of Turns
`N=200`

Length
`l=5cm to 10cm`

Voltage
`V=18V`

Magnetic field
`B=300mT`

Generally, the equation for Frequncy of an amarture is mathematically given by

`f =( V)/((N B A * 2 pi ))`

`f =( 18)/((200 300*10^(-3) (10*10^-2)(5*10^(-2)) * 2 *3.142 ))`

`f=9.55Hz`