Question

Use logarithmic differentiation to find dy/dx

Answer 1

Hello,

Explanation:

Let's say:

`y=x^(cotg(x))\\\\ln(y)=cotg(x)*ln(x)\\\\\\(y')/(y)=(-1)/(sin^2(x)) *ln(x)+(cotg(x))/(x) \\\\\\y'=-(x^(cotg(x))*ln(x))/(sin^2(x)) +cotg(x)*x^(cotg(x)-1)\\`