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A box of nine iPhone 5C cellphones (the iPhone “for the colorful”) contains two yellow cellphones and seven green cellphones. (a) If two cellphones are randomly selected from the box, without replacement (the first cellphone is not returned to the box after it is selected), what is the probability that both cellphones selected will be green? (b) If two cellphones are randomly selected from the box, without replacement (the first cellphone is not returned to the box after it is selected), what is the probability that there will be one yellow cellphone and one green cellphone selected? (c) If three cellphones are selected, with replacement (the first cellphones are returned to the box after it is selected), what is the probability that all three will be yellow? (d) If you were sampling with replacement (the first cellphone is returned to the box after it is selected), what would be the answers to (a) and (b)? 3

User Soydachi
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Final answer:

The probability calculations depend on whether the sampling is with or without replacement, affecting the odds after each selection. For without replacement, the odds change with each draw, while with replacement they remain constant.

Step-by-step explanation:

When dealing with probabilities of selecting specific items from a set without replacement, it is important to account for the changing odds after each selection. For example, if two cellphones are randomly selected from a box of two yellow and seven green iPhones without replacement, the probability that both are green is calculated by multiplying the probability of selecting a green iPhone on the first draw by the probability of selecting another green iPhone on the second draw after the first one has been removed.

The steps to calculate this probability would be to take the number of green phones over the total number of phones for the first draw: 7/9 then multiply by the number of remaining green phones over the new total for the second draw: 6/8, resulting in a probability of (7/9)*(6/8). Similarly, for the scenario where the colors are mixed (one yellow and one green), the calculations would involve selecting a yellow and then a green or vice versa.

When sampling with replacement, the total number of phones remains constant, and the probability of selecting a certain color remains unchanged with each draw. This results in a different probability calculation than when sampling without replacement.

User AlexTheo
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