Question

Rationalise the denominator of 2sq3+3sq2/4sq3+sq2​

Answer 1

`(9+5\sqrt6)/(23)`

Explanation:

We can rewrite the fraction as

`(2√(3)+3√(2))/(4√(3)+√(2))`

In order to rationalize the denominator of such a complex fraction, we must multiply the fraction by the conjugate of the denominator. In this case, the conjugate of the denominator would be
`4√(3)-√(2)`. Multiplying both sides of the fraction by the conjugate of the denominator would result in the fraction:

`(9+5\sqrt6)/(23)`