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The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 900 turns of largediameter wire, each of which carries a current of 14.0 kA. Find the magnitude of the magnetic field inside the toroid along (a) the inner radius and (b) the outer radius.

User Alexander Ibarra
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1 Answer

22 votes
22 votes

Answer:

(a) 11.3 T

(b) 6.09 T

Step-by-step explanation:

Current, I = 14 kA = 14000 A

number of turns, N = 900

inner radius, r = 0.7 m

outer radius, R = 1.3 m

The magnetic field due to a circular coil is given by


B = (\mu o)/(4\pi)* (2 N\pi I)/(R)

(a) The magnetic field due to the inner radius is


B = 10^(-7)* (2* 900* 3.14* 14000)/(0.7)\\\\B = 11.3 T

(b) The magnetic field due to the outer radius is


B = 10^(-7)* (2* 900* 3.14* 14000)/(1.3)\\\\B = 6.09 T

User Valikhan Akhmedov
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