Question

19. If 23.4 grams of hydrogen gas were produced by the reaction below, how many grams of aluminum chloride were produced? (2 points) 2 Al + 6 HCl yields 2 AlCl3 + 3 H2 516 g AlCl3 774 g AlCl3 1030 g AlCl3 1550 g AlCl3

Answer 1

1040

Step-by-step explanation:

you can use the mole to mole ratios of aluminum chloride and hydrogen gas,you first have to find the number of moles of hydrogen gas..the number of moles of hydrogen gas are 11.7(23.4/2)

2AlCl3+3H2

2 : 3

x :11.7

3x/3=23.4/3

x=7.8g/mol

then find the number of grams of aluminum chloride

m=n×mr

=7.8×133.341

=1040g

I hope this helps and sorry if it's wrong