Answer:
y = csc(x) does not have any zero.
Explanation:
If we have:
y = f(x)
a zero of that function would be a value x' such that:
y = f(x') = 0
Here we basically want to solve:
y = csc(x) = 0
First, remember that:
csc(x) = 1/sin(x)
now, the values of sin(x) range from -1 to 1.
So we want to solve:
1/sin(x) = 0
notice that a fraction:
a/b = 0
only if a = 0.
Then is easy to see that for our equation:
1/sin(x) = 0
The numerator is different than zero, then the equation never will be equal to zero.
Then:
y = csc(x) = 1/sin(x)
Does not have a zero.