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12 votes
12 votes
In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON​

In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular-example-1
User DreamHawk
by
3.5k points

2 Answers

25 votes
25 votes

DC=CF

  • Diameter=20cm
  • Radius=20/2=10cm

We know


\boxed{\sf L=(\theta)/(180)* πr}


\\ \large\sf\longmapsto L=(90)/(180)* (22)/(7)* 10


\\ \large\sf\longmapsto L=(1)/(2)* (220)/(7)


\\ \large\sf\longmapsto L=(110)/(7)


\\ \large\sf\longmapsto L=15.5

Now


\\ \large\sf\longmapsto CF=L+r-DE


\\ \large\sf\longmapsto CF=15.7+10-16


\\ \large\sf\longmapsto CF=25.7-16


\\ \large\sf\longmapsto CF=9.7cm

User Hannington Mambo
by
2.7k points
22 votes
22 votes


\large\sf\red{⟼L=18090×722×10}


\begin{gathered}\\ \large\sf\red{ ⟼ L=(1)/(2)* (220)/(7)}\end{gathered}


\begin{gathered}{ \large\sf\red{⟼ L=(110)/(7)}\end{gathered}

L=15.5

Now

CF=L+r−DE

CF=15.7+10−16

CF=25.7−16

⟼CF=9.7cm

User Tobia Zambon
by
2.8k points
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