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28 votes
28 votes
You are asked to build an LC circuit that oscillates at 13 kHz. In addition, you are told that the maximum current in the circuit can be 0.14 A and the maximum energy stored in the capacitor must be 1.4x10-5 J. What value of inductor and capacitor should you choose

User Moustafa Samir
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1 Answer

28 votes
28 votes

Answer:

a)
L=0.00142H

b)
C=2.65*10^(-12)

Step-by-step explanation:

From the question we are told that:

Frequency
F=13kHz

Current
I=0.14A

Capacitor
C_e=1.4*10^(-5)J

Generally the equation for Energy in the inductor is mathematically given by

Where L is now subject


L=(2C_e)/(I^2)


L=(2*1.4*10^(-5))/((0.14)^2)


L=0.00142H

Generally the equation for Value of Capacitor is mathematically given by


C=(1)/((2 \pi f)^2) L


C=(1)/((2 3.142 13*10^3Hz)^2) *0.00142


C=2.65*10^(-12)

User Anand Gaurav
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2.7k points