Question

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms. At what depth did this reflection occur? (The average propagation speed for sound in body tissue is 1540 m/s)

Answer 1

10.01 cm

Step-by-step explanation:

Given that,

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.

The average propagation speed for sound in body tissue is 1540 m/s.

We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

`v=(2d)/(t)\\\\d=(vt)/(2)\\\\d=(1540* 0.13* 10^(-3))/(2)\\\\d= $$0.1001\ m`

or

d = 10.01 cm

So, the reflection will occur at 10.01 cm.