Question

Let f(x)=x^2+2 and g(x)=1–3x. Find each function value:

1. (f+g)(-4)
2. (f•g)(-1)
3. g(f(-2))

Answer 1

Explanation:

To find (f + g)(-4), we need to evaluate f(-4) and g(-4) and then add those results together:

f(-4) =
`(-4)^2+2` so

f(-4) = 18

`g(-4)=1-3(-4)` so

g(-4) = 13

18 + 13 = 31; therefore, (f + g)(-4) = 31.

To find (f·g)(-1), we do the same: evaluate f(-1) and g(-1) and multiply those results together.

f(-1) = 3 and

g(-1) = 4 and

3 × 4 = 12; therefore (f·g)(-1) = 12.

To find g(f(-2)), we first evaluate f(-2), then plug that result into the g function.

f(-2) = 6 so

g(6) = -17