Question

A gas occupies 210 mL at -73°C to have the same gas occupy 360 mL:

should the temperature be increased or decreased?
what is the new temperature? __ K

Answer 1

a. The temperature should be increased.

b. 342.86K

Step-by-step explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question, the following information were given:

V1 = 210mL

V2 = 360mL

T1 = -73°C (-73 + 273 = 200K)

T2 = ?

Using V1/T1 = V2/T2

210/200 = 360/T2

Cross multiply

200 × 360 = 210 × T2

72000 = 210T2

T2 = 72000/210

T2 (new temperature) = 342.86K