Hi,there,can you solve this equation. 4x*sqrt(2x-x²)=2x-1

Charliefortune asked Feb 24, 2022

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28 votes

Hi,there,can you solve this equation.
4x*sqrt(2x-x²)=2x-1

Charliefortune asked Feb 24, 2022

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30 votes

Answer:

Explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 = 4x^2 -4x + 1

$-16x^4+32x^3-4x^2+4x-1=0\\$

x = 1.92887

Lanny answered Mar 2, 2022

by Lanny

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