Question

Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?

Answer 1

`V_(pp)=2V`

Step-by-step explanation:

Source Voltage
`V= 120V`

Frequency
`f=60Hz`

Peak output voltage
`Vp=15V`

Peak Output Voltage with filter
`V_p'=14V`

Generally the equation for Peak to peak voltage is mathematically given by

`V_p'=V_p-(V_(pp))/(2)`

Therefore

`V_(pp)=2(V_p-v_p')`

`V_(pp)=2(15-14)`

`V_(pp)=2V`