Question

a small table has a mass of 4kg, stands on four legs, each leg having an area of 0.001 m2. what is the pressure exerted by the table on the floor?

Answer 1

P = 10 kPa

Step-by-step explanation:

Given that,

The mass of a small table, m = 4 kg

The area of each leg = 0.001 m²

We need to find the pressure exerted by the table on the floor. Pressure is equal to the force per unit area. So

`P=(mg)/(4* A)\\\\P=(4* 10)/(4* 0.001)\\P=10000\ Pa\\\\or\\\\P=10\ kPa`

So, the required pressure is 10 kPa.