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39 votes
Find the missing side lengths

Find the missing side lengths-example-1
User Adeel Shekhani
by
2.4k points

1 Answer

9 votes
9 votes

Answer:


Sin \: 60=(√(3) )/(u)


u=√(3) /sin\:60


u=√(3) /√(3) /2


u=2

..........................


Cos\: 60=(v)/(2)


v=2\: cos\:60


v=2((1)/(2))


v=1

OAmalOHopeO

User Yousef Zakher
by
2.7k points