Question

Question

Find an equation of a line that contains the points (-3, -1) and (2, -2). Write the equation in slope-intercept form.

Answer 1

y=-1/5x-8/5

Explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-1))/(2-(-3))

m=(-2+1)/(2+3)

m=-1/5

y-y1=m(x-x1)

y-(-1)=-1/5(x-(-3))

y+1=-1/5(x+3)

y=-1/5x-3/5-1

y=-1/5x-3/5-5/5

y=-1/5x-8/5