Question

Two buses leave towns 576 kilometers apart at the same time and travel toward each other. One bus travels 12

h
slower than the other. If they meet in 3 hours, what is the rate of each bus?
km
Rate of the slower bus:

Rate of the faster bus:

Answer 1

102 km/hr

90 km/hr

Explanation:

Given that :

Total distance = 576

Time taken = 3 hours

Bus A :

Speed = x

Bus B :

Speed = x - 12

Recall :

Distance = speed * time

Hence,

Distance covered by A + Distance covered by B = total distance covered

(x * 3) + ((x - 12) * 3) = 576

3x + 3x - 36 = 576

6x = 576 + 36

6x = 612

x = 612 / 6

x = 102

Speed of faster bus, x = 102 km/h

Speed of slower bus, x - 12 = (102 - 12) = 90 km/hr