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In a circle with a diameter of 32, the area of a sector is 512(pi)/3. The measure of the angle of a sector in radians is

A.) π/3
B.) 4π/3
C.)16π/3
D.)64π/3

1 Answer

6 votes

Answer:

B

Explanation:


\boxed{area \: of \: sector = (1)/(2) {r}^(2) θ }

Radius= diameter ÷2

r= 32 ÷2

r= 16


(1)/(2) {r}^(2) θ = (512\pi)/(3)

Substitute r= 16,


(1)/(2) ( {16}^(2) )(θ) = (512\pi)/(3)


128 \: θ = (512\pi)/(3) \\ θ = (512\pi)/(3) / 128 \\ θ = (512\pi)/(384)

Divide the denominator and numerator by 128:


θ = (4\pi)/(3)

Thus, the answer is B.

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