Question

What is the solution to -4(8-3x)>6x-8?

O x > -4/3
O x < -4/3
O x > 4
O x < 4

Answer 1

x
`\geq` 4

Explanation:

-4(8-3x)
`\geq`6x-8 multiply inside the parenthesis with -4

12x - 32
`\geq` 6x - 8 export like terms to the same side of the inequality

12x - 6x
`\geq` 32 - 8

6x
`\geq` 24 divide both sides by 6

x
`\geq` 4

Answer 2

Given :

What is the solution to -4(8 - 3x) ≥ 6x - 8 ?

Solution :

Assume this ≥ sign as = sign

• - 4(8 - 3x) ≥ 6x - 8

By simplifying the left hand side we get

• - 32 + 12x ≥ 6x - 8

Transposing them to the other side

• 12x - 6x ≥ 32 - 8

• 6x ≥ 24

• x ≥ 24/6

• x ≥ 4

Hence, the correct answer is the third option i.e. x ≥ 4