72.7k views
22 votes
NO WRONY ANSWERS PLEASE

NO WRONY ANSWERS PLEASE-example-1
User Rebeling
by
5.2k points

1 Answer

5 votes

9514 1404 393

Answer:

D. both B and C

Explanation:

The radius of the pond and border is (x+1). Then the diameter of the pond and border is 2(x+1) = 2x+2. The width of the square yard is 6 more, so is (2x +2) +6. = 2x +8.

The area of the yard is the square of the width: (2x +8)^2, and the area of the pond is pi times the square of its radius: π(x +1)^2.

The non-pond area of the yard is the difference of these:

non-pond area = (2x +8)^2 -π(x +1)^2

= (4x^2 +32x +64) -π(x^2 +2x +1) . . . . . . matches B

= (4 -π)x^2 +(32 -2π)x +(64 -π) . . . . . . . . matches C

User L P
by
5.2k points