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During the 5 minute period described in question 4, the water in the insulated vessel undergoes a temperature increase of 20 C. Assuming all of the electrical energy dissipated by the resistor was transferred to the water as heat, what is the mass of the water

User Attila Szili
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1 Answer

27 votes
27 votes

Answer:

Please find the complete question in the attached file.

Step-by-step explanation:


V=12\ V\\\\I=1.2\ A\\\\T=5* 60=300\ second\\\\

Calculating the electrical energy dissipated:


w=p\cdot t=V\cdot I \cdot t\\\\


=12* 1.2 * 300 \ J\\\\=4320\ J


\Delta T=20^(\circ)\ C\\\\W=m\cdot c\cdot \Delta T\\\\4320=m(4186 * 20)\\\\m=(4320)/(4186 * 20)=51.6 \ grams=0.516 \ kg\\\\

During the 5 minute period described in question 4, the water in the insulated vessel-example-1
User Ahmed Safadi
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