Question

When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy

is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)

Answer 1

Q = 194.34 J

Step-by-step explanation:

Given that,

100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.

We need to find the amount of thermal energy absorbed by the ethyl alcohol.

The density of ethyl alcohol is 0.790 g/mL.

The formula for heat absorbed is given by :

`Q=mc\Delta T\\\\As, d=(m)/(V)\\\\So,\\Q=dVc\Delta T\\\\Q=0.79* 100* 2.46\\\\Q=194.34\ J`

So, 194.34 J of thermal energy is absorbed by the ethyl alcohol.