Answer:
9.81 J
Step-by-step explanation:
The 10 kg block shown in the figure is in contact with the spring that has a natural length of 25 cm. When the block is released, it compresses the spring, remaining static 15 cm from the floor. Calculate the change in elastic potential energy of the spring in Joules
The given parameters are;
The mass of the block in contact with the spring = 10 kg
The natural length of the spring = 25 cm
The final height of the block after being released = 15 cm
Therefore;
The potential energy of the block = m·g·h
The initial potential energy of the block = 10 kg × 9.81 m/s² × 0.25 m = 24.252 J
The final potential energy of the block = 10 kg × 9.81 m/s² × 0.15 m = 14.715 J
By energy conservation principle
The change in potential energy of the block = The change in elastic potential energy of the spring = (1/2)·k·x² = 24.252 J - 14.715 J = 9.81 J