Question

A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the probability both beads drawn are green.

A.6/7
B.6/49
C.16/49
D.9/49

Answer 1

9/49

Explanation:

4 purple beads and 3 green beads. = 7 beads

P(green) = green / total = 3/7

It is replaced

4 purple beads and 3 green beads. = 7 beads

P(green) = green / total = 3/7

P( green ,replaced, green) = 3/7 * 3/7 = 9/49