Answer:
Explanation:
The following configured particulars are states, in accordance by the interrogate:
Perimeter = 96 hectometers.
Assuming the figure is a square, we can assume that,
S = A side length where,
4s = 96, where all side lengths are equivalent.
If so, then s = 24
Thus, that means that w, denoted as width, must be less than or equal to 24.
In addition, likewise, l, denoted as length, must be less than or equal to 24.
Furthermore, the length is acknowledged or stated to be twice that of the width:
Length = 2w
The listed above may be equated to the following:
2w + 2L = 96
2(24) + 2L = 96
2L + 48 = 96
2L = 48
L = 24
Thus, the width of the figure is equivalent to 24. (Length divided by two).
Thus, the length of the figure is equivalent to 24 (twice the width).
*I hope this helps.