Question

52 POINTS I need help!

Question 1

The vertex form of the equation of a vertical parabola is given by
, where (h, k) is the vertex of the parabola and the absolute value of p is the distance from the vertex to the focus, which is also the distance from the vertex to the directrix. You will use the GeoGebra geometry tool to create a vertical parabola and write the vertex form of its equation. Open GeoGebra, and complete each step below. If you need help, follow these instructions for using GeoGebra.

Part A

Mark the focus of the parabola you are going to create at F(6, 4). Draw a horizontal line that is 6 units below the focus. This line will be the directrix of your parabola. What is the equation of the line?
Part B

Construct the line that is perpendicular to the directrix and passes through the focus. This line will be the axis of symmetry of the parabola. What are the coordinates of the point of intersection, A, of the axis of symmetry and the directrix of the parabola?
Part C

Explain how you can locate the vertex, V, of the parabola with the given focus and directrix. Write the coordinates of the vertex.
Part D

Which way will the parabola open? Explain.
Part E

How can you find the value of p? Is the value of p for your parabola positive or negative? Explain.
Part F

What is the value of p for your parabola?
Part G

Based on your responses to parts C and E above, write the equation of the parabola in vertex form. Show your work.
Part H

Construct the parabola using the parabola tool in GeoGebra. Take a screenshot of your work, save it, and insert the image below.
Part I

Once you have constructed the parabola, use GeoGebra to display its equation. In the space below, rearrange the equation of the parabola shown in GeoGebra, and check whether it matches the equation in the vertex form that you wrote in part G. Show your work.
Part J

To practice writing the equations of vertical parabolas, write the equations of these parabolas in vertex form:

focus at (-5, -3), and directrix y = -6
focus at (10, -4), and directrix y = 6.

Answer 1

the one above is correct

Explanation:

h.We start with a circle and a line that goes through the center of the circle (C) and one vertex of the triangle (E).

Using the point on the line opposite the vertex as a center (D), we draw an arc with the same radius the circle has.

The two points of intersection with the circle are the other two vertices of the inscribed triangle (F, G).

Answer 2

Explanation:

A. Directrix: y = 4-6 = -2

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B. Axis of symmetry: x = 6

Axis of symmetry intersects directrix at (6,-2)

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C . Vertex is halfway between focus and directrix, at (6,1)

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D. The focus lies above the directrix, so the parabola opens upwards.

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E. Focal length p = 1/(4×0.5)

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F. p = 0.5

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G. y = 0.5(x-6)² + 1