Question

& Oregonians eat about 9503 metric tons of food each day. What is this consumption rate in grams

per second?

Answer 1

109988 grams per second

Step-by-step explanation:

To solve this problem first we convert 9503 metric tons into grams, keeping in mind that:

• 1 metric ton = 1000 kg

• 1 kg = 1000 g

Meaning that:

• 9503 metric ton *
  `(1000kg)/(1metricTon)*(1000g)/(1kg)` = 9503x10⁶ g

Then we calculate how many seconds are there in one day:

• 1 day *
  `(24h)/(1day) *(60min)/(1h) * (60s)/(1min)` = 86400 s

Finally we calculate the consumption rate:

• 9503x10⁶ g / 86400 s = 109988 g/s