Answer:
0.116%
Step-by-step explanation:
efficiency of sterling engine = 1 - ( 55 + 273 )k / ( 95 + 273 ) k
= 1 - ( 328 / 368 ) = 0.10869
Determine how efficient the transfer of energy via flame is
apply this relation ; energy of steady state / energy output ---- ( 1 )
where; energy output = efficiency of sterling engine * energy
= 0.10869 * 50 = 5.4345 J/sec
energy of steady state = 1/2 * I * w^2 ------ ( 2 )
I = moment of inertia of engine = 2 * 10^-5 kgm^2
back to equation 2 :
energy of steady state = 1/2 * ( 2 * 10^-5 ) * ( 240 * 2π / 60 )^2
= 630.88 * 10^-5 J /sec
Input values into equation 1
= [ (630.88 * 10^-5 ) / 5.4345 ] * 100
= 0.116%