Question

Take a factor out of the square root: 48x^2 , where x≤0

Answer 1

`-4x√(3)`

Explanation:

One is given the following expression:

`√(48x^2)`

Factor out the expression. Rewrite the expression as the product of a number times itself times another number. This will allow one to take factors out of the radical. Remember, the square root operation indicates that a number times itself equals the number under the radical. Bear in mind, the result of the square root operation must always be positive. Since (x) is negative, one has to multiply the result of the operation by (-1) to compensate for the fact that (x) is negative. Rewrite the value under the radical:

`√(4*4*3*x^2)`

Take out the factors,

`=-4x√(3)`