Question

The length of a rectangle is 2 cm longer than its width.

If the perimeter of the rectangle is 36 cm, find its area.

Answer 1

Explanation:

let x be the width

p=2l+2w

36=2(2)+2(x)

36=4+2x

36-4=2x

32/2=2x/2(simplify)

x=16

therefore the width is 16cm

area of the rectangle is l×w

=2×16

=32cm"

therefore the area is 32cm"

Answer 2

80 cm^2

Explanation:

Let the width of the rectangle equal x. This means the length is x + 2, as it is 2 cm longer than the width. The formula for perimeter is: P = 2l + 2w, and substitute in the values of the length, width, and perimeter:

P = 2l + 2w

36 = 2(x + 2) + 2(x)

36 = 2x + 4 + 2x

36 = 4x + 4

4x = 32

x = 8

x represents the width, so the width is 8 and the length is 10. Area is length times width, so the area is 8 x 10 or 80 cm^2.