2 Answers

Samblg · Answer 1 · 2022-04-11T22:59:40+0000

Answer:

100. mL

Step-by-step explanation:

The computation of the volume in mL is shown below:

The balance equation of the double displacement reaction is

$CaCl_(2) + Na_(2)CO_(3) \rightarrow 2 NaCl + CaCO_(3)$

Now determine the moles that corresponding to 1.00 g of CaCO₃

As,

The molar mass of CaCO₃ is 100.09 g/mol.

So,

= 1.00 g × 1 mol/100.09 g

= 0.0100 mol

Now

the moles of CaCl₂ needed to generate 0.0100 moles of CaCO₃

As we know that

The molar ratio of CaCl₂ to CaCO₃ is 1:1.

So, The moles of CaCl₂ needed is

= 1 ÷ 1 × 0.0100 mol

= 0.0100 mol.

Now volume of 0.100 M CaCl₂ that contains 0.0100 mol is

= 0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L

= 100. mL

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