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Identify the equation of the circle that has its center at (9, 12) and passes through the origin.

Identify the equation of the circle that has its center at (9, 12) and passes through-example-1
User Simplename
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1 Answer

16 votes
16 votes

Answer:

(x-9)^2 +(y-12)^2 = 225

Explanation:

First find the length of the radius

If is the distance from the center to the point

d = sqrt( (x2-x1)^2 + (y2-y1)^2 )

= sqrt( (0-9)^2 + (0-12)^2)

= sqrt ( 81+144)

= sqrt(225)

= 15

The equation for a circle is

( x-h) ^2+ (y-k)^2 = r^2

(x-9)^2 +(y-12)^2 = 15^2

(x-9)^2 +(y-12)^2 = 225

User TomRoche
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