Answer:
this has no real solution.
only in the realm of complex and imaginary numbers.
x = 1/3 ± sqrt(11)i/3
Explanation:
I read as the equation to be solved :
3x² - 2x + 4 = 0
the solution to such a quadratic equation is
x =(-b ± sqrt(b² - 4ac))/(2a)
in our case
a=3
b=-2
c=4
so,
x = (2 ± sqrt(4 - 48))/6 = (2 ± sqrt(-44))/6 =
= (2 ± sqrt(4×-11))/6 = (2 ± 2×sqrt(-11))/6 =
= (1 ± sqrt(11)×i)/3 = 1/3 ± sqrt(11)i/3