Question

The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 1.6 µC, and the distance between them is d = 2.6 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings.

Answer 1

a)
`F = 6816.5680 N`

b)
`F' = 0 N`

c)
`F''=28195.5N`

Step-by-step explanation:

Magnitude of charges
`M=1.6\muC`

Distance
`d=2.6`

Generally the equation for Net Force is mathematically given by

For First Drawing

`F =( k q^2)/(d^2)+(k q^2)/(d^2)`

`F =(2* 9*10^9* (1.6*10^-6)^2)/( (2.6*10^-3^2)`

`F = 6816.5680 N`

For second Drawing

`F' =( k q^2)/(d^2 )-( k q^2)/( d^2)`

`F' = 0 N`

For Third Drawing

`F'' =( k q^2)/(d^2) * \sqrt (2)`

`F'' = 9*10^9* (6.4*10^-6)^2 * (\sqrt(2))/((4.3*10^-3)^2)`

`F''=28195.5N`