Question

What is the eqution of the line through the orgin and (-2,3)

Answer 1

-2y+3x=0

Explanation:

Slop=(3-0)/(-2-0)=-3/2

(Y-Y1) =m(x-x1)

(y-3) =-3/2(x+2)

-2y+3x=0

Answer 2

Origin = (0, 0)

Gradient or slope:

`{ \tt{slope = ((0 - 3))/((0 - ( - 2))) }} \\ { \tt{slope = - (3)/(2) }}`

General equation of line:

`{ \bf{y = mx + c}}`

Consider the origin:

`{ \tt{0 = ( - (3)/(2) * 0) + c }} \\ c = 0`

Equation of line:

`{ \tt{y = - (3)/(2)x }} \\ { \tt{2y = - 3x}}`