Answer:
38.34 g of HCN are produced
Step-by-step explanation:
Our reactants for the first reaction are:
NH₃ and O₂
Products are: H₂O and NO
Our reactants for the second reaction are:
NO and CH₄
Producs are: H₂, H₂O and HCN
The reactions are:
4NH₃ and 5O₂ → 6H₂O + 4NO
2NO and 2CH₄ → 2HCN + H₂ + 2H₂O
In the first step 4 moles of ammonia can produce 4 moles of NO, so ratio is 1:1
24.2 g . 1mol / 17 g = 1.42 moles of ammonia
We have produced 1.42 moles of NO.
25.1 g . 1 mol / 16 g = 1.57 moles of methane.
Ratio is 2:2. So, for 1.57 moles of methane, we need 1.57 moles of NO.
Moles are the same. As there is no enough NO, this is the limiting reactant.
Ratio with product is also 2:2.
Our 1.42 moles of NO have produced 1.42 moles of HCN.
We convert moles to mass: 1.42 mol . 27 g/mol = 38.34 g